Integrand size = 14, antiderivative size = 25 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^5} \, dx=-\frac {9}{4 x^4}+\frac {8}{x^3}-\frac {11}{x^2}+\frac {8}{x}+\log (x) \]
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Time = 0.01 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {712} \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^5} \, dx=-\frac {9}{4 x^4}+\frac {8}{x^3}-\frac {11}{x^2}+\frac {8}{x}+\log (x) \]
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Rule 712
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {9}{x^5}-\frac {24}{x^4}+\frac {22}{x^3}-\frac {8}{x^2}+\frac {1}{x}\right ) \, dx \\ & = -\frac {9}{4 x^4}+\frac {8}{x^3}-\frac {11}{x^2}+\frac {8}{x}+\log (x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^5} \, dx=-\frac {9}{4 x^4}+\frac {8}{x^3}-\frac {11}{x^2}+\frac {8}{x}+\log (x) \]
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Time = 13.47 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.92
method | result | size |
norman | \(\frac {-\frac {9}{4}+8 x^{3}-11 x^{2}+8 x}{x^{4}}+\ln \left (x \right )\) | \(23\) |
risch | \(\frac {-\frac {9}{4}+8 x^{3}-11 x^{2}+8 x}{x^{4}}+\ln \left (x \right )\) | \(23\) |
default | \(-\frac {9}{4 x^{4}}+\frac {8}{x^{3}}-\frac {11}{x^{2}}+\frac {8}{x}+\ln \left (x \right )\) | \(24\) |
parallelrisch | \(\frac {4 \ln \left (x \right ) x^{4}-9+32 x^{3}-44 x^{2}+32 x}{4 x^{4}}\) | \(28\) |
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Time = 0.28 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.08 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^5} \, dx=\frac {4 \, x^{4} \log \left (x\right ) + 32 \, x^{3} - 44 \, x^{2} + 32 \, x - 9}{4 \, x^{4}} \]
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Time = 0.04 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.88 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^5} \, dx=\log {\left (x \right )} + \frac {32 x^{3} - 44 x^{2} + 32 x - 9}{4 x^{4}} \]
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none
Time = 0.19 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.92 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^5} \, dx=\frac {32 \, x^{3} - 44 \, x^{2} + 32 \, x - 9}{4 \, x^{4}} + \log \left (x\right ) \]
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none
Time = 0.27 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.96 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^5} \, dx=\frac {32 \, x^{3} - 44 \, x^{2} + 32 \, x - 9}{4 \, x^{4}} + \log \left ({\left | x \right |}\right ) \]
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Time = 0.02 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.88 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^5} \, dx=\ln \left (x\right )+\frac {8\,x^3-11\,x^2+8\,x-\frac {9}{4}}{x^4} \]
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